已知数据格式，实现一个函数 fn 找出链条中所有的父级 id ​

const list = [{
    id: '1',
    name: 'test1',
    children: [
        {
            id: '11',
            name: 'test11',
            children: [
                {
                    id: '111',
                    name: 'test111'
                },
                {
                    id: '112',
                    name: 'test112'
                }
            ]

        },
        {
            id: '12',
            name: 'test12',
            children: [
                {
                    id: '121',
                    name: 'test121'
                },
                {
                    id: '122',
                    name: 'test122'
                }
            ]
        }
    ]
}];
const id = '112'
const fn = (value) => {
...
}
fn(id, list) // 输出 [1， 11， 112]

const list = [{
    id: '1',
    name: 'test1',
    children: [
        {
            id: '11',
            name: 'test11',
            children: [
                {
                    id: '111',
                    name: 'test111'
                },
                {
                    id: '112',
                    name: 'test112'
                }
            ]

        },
        {
            id: '12',
            name: 'test12',
            children: [
                {
                    id: '121',
                    name: 'test121'
                },
                {
                    id: '122',
                    name: 'test122'
                }
            ]
        }
    ]
}];
const id = '112'
const fn = (value) => {
...
}
fn(id, list) // 输出 [1， 11， 112]

function fn(id, list) {
  const match = list.find(item => item.id === id);
  if (match) return [id];
  const sub = list.find(item => id.startsWith(item.id));
  return [sub.id].concat(fn(id, sub.children));
}

function fn(id, list) {
  const match = list.find(item => item.id === id);
  if (match) return [id];
  const sub = list.find(item => id.startsWith(item.id));
  return [sub.id].concat(fn(id, sub.children));
}